Solutions To Mathematics Textbooks/Basic Mathematics/Chapter 2: Difference between revisions

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Latest revision as of 06:50, 13 January 2021

Chapter 2

Section 1

11

$a x + b y = u$

$c x + d y = v$

$a c x + b c y = u c$

$a c x + a d y = v a$

$(a c x + b c y) - (a c x + a d y) = u c - v a$

$b c y - a d y = u c - v a$

$y (b c - a d) = u c - v a$

$y = \frac{u c - v a}{b c - a d}$

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