Topics in Abstract Algebra/Non-commutative rings: Difference between revisions

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Latest revision as of 21:01, 25 December 2019

A ring is not necessarily commutative but is assumed to have the multiplicative identity.

{{Template:BOOKTEMPLATE/Theorem |theorem=Proposition |label= |claim=Let R be a simple ring. Then: every morphism RR is either zero or an isomorphism. (Schur's lemma)}}


{{Template:BOOKTEMPLATE/Theorem |theorem=Theorem |label= |name=Levitzky |claim=Let R be a right noetherian ring. Then every (left or right) nil ideal is nilpotent.}}

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