Puzzles/Geometric Puzzles/Rectangle and Circle/Solution

Answer

30 inches

Tools Used to Solve

Pythagorean Theorem

Quadratic Formula

Solution

Given:

$x=12in$

$y=6in$

Find:

$r=?$

We realize that every point on a circle is equidistant from the origin. This implies that the rectangle's corner touching the circle must be r inches away from the origin, where r is the radius. We can then draw a right triangle with sides $r-y$ and $r-x.$ Now apply the Pythagorean Theorem to this triangle and solve for r.

$(r-x{)}^2+(r-y{)}^2=r^2$

$r^2-2r(x+y)+x^2+y^2=0$

The above equation is quadratic and can be solved by applying the Quadratic Formula.

$r=\frac{2(x+y)\pm \sqrt{(4(x+y{)}^2-4(x^2+y^2)}}{2}$

Which simplifies to,

$r=(x+y)\pm \sqrt{2xy}$

Now we can plug in our numbers and solve,

$r=(6+12)\pm \sqrt{2(6)(12)}$

$r=18\pm 12$

$r=30$ or $r=6$

Thus the radius of our circle is 30 inches. Notice that 6 inches is not a valid answer. Why?

Comment: Simply making a statement that "we can then draw..." is confusing. Need more explanation on why r-x and r-y are valid descriptors for the triangle sides. This is easier to see with the r-x side than with the r-y.