Linear Algebra with Differential Equations/Heterogeneous Linear Differential Equations/Variation of Parameters

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As with the variation of parameters in the normal differential equations (a lot of similarities here!) we take a fundamental solution and by using a product with a to-be-found vector, see if we can come upon another independent solution by these means. In other words, since the general solution can be expressed as ๐œψ where ๐œ is the constant matrix and ψ is the augmented set of independent solutions to the homogeneous equation, we try out a form like so:

๐—=๐ฎψ

And determine ๐ฎ to find a unique solution. The math is fairly straightforward and left as an exercise for the reader, and leaves us with:

๐—=ψ(t)ψ1(t0)๐—0+ψ(t)t0tψ1(s)๐ (s)ds

... which is a fairly strong, striaghtforward, yet exceedingly complicated formula.

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