rate=k[A]m[B]n
order of reaction=m+n
k=Ae−EaRT
ln(k)=ln(Ae−EaRT)
ln(k)=ln(A)+ln(e−EaRT)
ln(k)=ln(A)+−EaRT
ln(k)=ln(A)−EaRT
ln(k)=−EaRT+ln(A)
ln(k)=−EaR1T+ln(A)
straight-line graphs are always of the form y=mx+c
therefore, the dependent variable y is ln(k)
the gradient m is −EaR
the independent variable x is 1T
the y-intercept c is ln(A)
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