Solutions To Mathematics Textbooks/Calculus Early Transcendentals (6th) (0495011665)/Chapter 1.1

Chapter 1.1 Exercises

25

Replace instances of $f(x)$ with the expression $\frac{1}{x}$.

$\frac{\frac{1}{x}-\frac{1}{a}}{x-a}=(\frac{1}{x}-\frac{1}{a})\cdot \frac{1}{x-a}$

$=\frac{a-x}{xa(x-a)}=\frac{(a-x)}{-xa(a-x)}=-\frac{1}{ax}$