Q1 answer:dydx+2y=x2e−2x+5y=∫e∫P(x)dxQ(x)dx+Ce∫P(x)dxe∫P(x)dxP(x)=2e∫2dx=e2xQ(x)=x2e−2x+5y=∫(e2x)(x2e−2x+5)dx+Ce2xy=∫x2+5e2xdx+Ce2x=x33+5e2x2+Ce2xy=x33e2x+52+Ce2x_ Template:BookCat