A-level Mathematics/MEI/FP1/Complex Numbers/argand diagram answers
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1.
z
=
2
0
+
0
j
wanted form =
z
=
r
(
c
o
s
θ
+
j
s
i
n
θ
)
r
=
2
0
2
+
0
2
=
2
0
t
a
n
(
0
2
0
)
=
0
z
=
2
0
(
c
o
s
(
0
)
+
j
s
i
n
(
0
)
)
2.
z
=
0
+
1
2
j
wanted form =
z
=
r
(
c
o
s
θ
+
j
s
i
n
θ
)
r
=
(
0
2
+
1
2
2
)
=
1
2
t
a
n
(
1
2
e
m
0
)
=
∞
t
a
n
−
1
(
∞
)
=
π
2
- You need to look at the graph to get this really. Using Sine or Cosine may be advisable in this situation.
z
=
1
2
(
c
o
s
(
π
2
)
+
j
s
i
n
(
π
2
)
)
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