A-level Mathematics/MEI/FP1/Complex Numbers/argand diagram answers

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1.

z=20+0j
wanted form = z=r(cosθ+jsinθ)
r=202+02=20
tan(020)=0
z=20(cos(0)+jsin(0))

2.

z=0+12j
wanted form = z=r(cosθ+jsinθ)
r=(02+122)=12
tan(12em0)=
tan1()=π2 - You need to look at the graph to get this really. Using Sine or Cosine may be advisable in this situation.
z=12(cos(π2)+jsin(π2))

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