Electronic Properties of Materials/Quantum Mechanics for Engineers/Perturbation Methods

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This is the ninth chapter of the first section of the book Electronic Properties of Materials.

**INCOMPLETE**


Most operators (Hamiltonians) are not simple. Fortunately, with a bit of effort, we can sometimes rewrite the operator (H^) as H^=H^o+λH, where H^ is a Hamiltonian for which we know the solution.

H^o ψη(o)=Eη(o) ψη(o)

Here, ψη(o) are non degeneratory orthogonal eigenfunctions, and H is a small perturbation to the Ho. Additionally, λ is a real arbitrary parameter, and when λ=0, we have:

H=Ho  when λ=1H=Ho+H

The problem we want to solve is: Hψη=Eηψη

The perturbation is small and in the limit λ goes to zero.

Eη=Eη(o)+ψη=ψη(o)

We will assume that Eη and ψη can be written as powers of λ.

Eη=j=0λjEη(j)=Eη(o)+λEη(1)+λ2Eη(2)++λnEη(n)ψη=j=0λkψη(j)

Substituting:

(Ho+λH)(ψη(o)+λψη(1)+λ2ψη(o)++λnψη(n))=(Eη(o)+λEη(1)+λ2Eη(o)++λnEη(n))(ψη(o)+λψη(1)+λ2ψη(o)++λnψη(n))

Multiply through & collect common properties to form equations for each power of λ:λo:Hoψn(o)=En(o)ψn(o)λ1:Hoψn(1)+Hψ(o)=En(o)ψn(1)+En(1)ψn(o)λ2:Hoψn(2)+Hψ(1)=En(0)ψn(2)+En(1)ψn(1)+En(2)ψn(o)

The powers of λo are just our unperturbed Ho. We will begin by looking at powers of λ1.

Rearrange:

(HoEn(o))ψn(1)+(HEn(1))ψn(o)=0

multiply left by ψn*(o) and integrate

ψn*(o)(HoEn(o))ψn(1)+ψn*(o)(HEn(1))ψn(o)=0

Begin with left term. These operators are Hermitian. They have special properties, namely that they obey the postulates of quantum mechanics, including a few revations that are useful for proofs. One such property is:

Ψ*HΦ=(Φ*HΨ)*

Which we will use here:

ψn(o)*Hoψn(1)=(ψn(1)*Hψn(o))*=(ψn(1)*En(o)ψn(o))*=En(o)(ψn(1)*ψn(o))*=En(o)ψn(o)*ψn(1)

Thus, our entire term equals zero. As a result:

ψn(o)Hψn(o)=En(1)ψn(o)*ψn(o)=En(1)

Therefore, the first order correction to the eigenvalue is:

En(1)=ψn(o)*Hψn(o)

Following the same steps we can find the higher order perturbations:

En(2)=ψn(o)*(HEn(1))ψn(1)En(3)=ψn(1)*(HEn(1))ψn(1)2En(2)ψn(o)*ψn(1)

Most simple theories do not require these higher order corrections, but how do we get the wavefunctions in the first place? Lets assume that ψn(1)=kank(1)ψk(o) where ank coefficient is the projection of ψn(1) onto ψk(o). Returning to our original λ term, gather:

Hoψn(1)+Hψn(o)=En(o)ψn(1)+En(1)ψn(o)

Rearranging and substituting gives us:

0=(HoEn(o))an(1)ψk(o)+(HEn(1))ψn(o)

Multiplying the right side by ψ(o)*and integrating gets us:

0=ψ(o)*En(o)ank(1)ψk(o)En(o)ψ(o)*kank(1)ψk(o)+ψ(o)*Hψn(o)En(1)ψ(o)*ψn(o)=E(o)an(1)En(o)an(1)+ψ(o)*Hψn(o)En(1)δn

When n=, we loose all an(1) terms, giving us: En(1)=ψ(o)*Hψn(o)

However, when n we get:

0=(E(o)En(1))an(1)+ψ(o)*Hψn(o)an=ψ(o)*Hψn(o)E(o)En(o)

Since ann(1) does not seem to be determined from these equations, there is an uncomfortable degree of arbitrariness in selecting ann(1). Require normalization:

1=Ψ*ψ1+0(λj+1)=(ψn*(o)+λψn*(1)+λ2ψn*2+)(ψn(o)+λψn(1)+λ2ψn(2)+)

Where: λo: 1=ψn(o)*ψn(o)λ1: 0=ψn(0)*ψn(1)+ψn(1)*ψn(o)λ3: 0=ψn(0)*ψn(2)+ψn(1)*ψn(1)+ψn(2)*ψn(o)

Thus:

0=ψn(o)*ψn(1)=ann+ψn(1)*ψn(o)=ann(1)*

which is a projection of ψn(1) onto ψn(o).

ann(1)+ann(1)*=0 is a complex number.

Complex number formula: 0=a+bi+abi0=a

What is b? Here, we choose b=0.

<FIGURE> "Title" (Description)

In quantum mechanics usually, but not always, Ψ can have arbitrary phase ϕ, so long as magnitude of Ψ is correct. Here we choose ϕ=0. Therefore:

ann(1)=0

This dictates that all of ψn(1) is orthogonal to ψn(o).

As an example, consider adding a correction to the hydrogen atom, what is actually a fairly common occurrence.

H=Ho+HHo=22mΔ2e2rH=GmMpr

This last equation is the influence of gravitational attraction between the positive ion and the negative ion. This is a first order energy correction.

E1s(1)=ψ1s(o)*(GmMpr)ψ1s(o)drightψ1s(o)=1π1ao32exp[2rao]GmMrE1s(1)=0πsinθdθ02πdϕ0r2dr1π1aoexp[2rao]GmMao2(ao24)=4πGmMπao30drrexp[2rao]=4GmMao3(ao24)

When working with degenerate wavefunctions, the problem becomes slightly more complicated because the interactions amongst the degenerate wavefunctions must be carefully accounted for. That said, this is just bookkeeping. The general procedure for Rayleigh-Schrodinger perturbation theory is as outlined here.

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