Introduction to Mathematical Physics/Quantum mechanics/Linear response in quantum mechanics

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Let <A>(t) be the average of operator (observable) A. This average is accessible to the experimentator (see (references)). The case where H(t) is proportional to sin(ωt) is treated in (references) Case where H(t) is proportional to δ(t) is treated here. Consider following problem: Template:IMP/prob Template:IMP/rem Using the interaction representation\footnote{ This change of representation is equivalent to a WKB method. Indeed, ψ(t)~ becomes a slowly varying function of t since temporal dependence is absorbed by operator eiH0t} Template:IMP/eq and Template:IMP/eq Quantity <qZ> to be evaluated is: Template:IMP/eq Template:IMP/eq At zeroth order: Template:IMP/eq Thus: Template:IMP/eq Now, ψ~ has been prepared in the state ψ0, so: Template:IMP/eq At first order: Template:IMP/eq thus, using properties of δ Dirac distribution: Template:IMP/eq Let us now calculate the average: Up to first order,

<qZ>=<ψ~0+ψ1~|eiH0tqZeiH0t|ψ~0+ψ1~>=<ψ~0|eiH0tqZeiH0t|ψ~1>+<ψ~1|eiH0tqZeiH0t|ψ~0>

Indeed, <ψ~0|qZ|ψ~0> is zero because Z is an odd operator.

<ψ~0|eiH0tqZeiH0t|ψ~1>==<ψ~0|eiH0tqZeiH0t|ψk><ψk|ψ~1>

where, closure relation has been used. Using perturbation results given by equation ---pert1--- and equation ---pert2---: Template:IMP/eq We have thus:

<qZ>(t)=0 if t<0<qZ>(t)=eiω0kt<ψ0|qZ|ψk>1i<ψk|Wic|ψ0>+CC if not 

Using Fourier transform\footnote{ Fourier transform of: Template:IMP/eq and Fourier transform of: Template:IMP/eq are different: Fourier transform of f(t) does not exist! (see (references)) }

Template:IMP/eq

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