Math for Non-Geeks/Unbounded sequences diverge
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In this chapter we will see that unbounded sequences must diverge. From this we can follow that convergent sequences must be bounded.
Unbounded sequences diverge
In the chapter How to prove convergence and divergence we have already seen that the sequence diverges. We used the property that the sequence grows beyond any boundary. That is to say if we have fixed, then there exists with . Also for all with we have and thus
Infinitely many members lie outside of the -neighbourhood . Therefore cannot converge towards . If that were the case almost all members would have to be contained inside , which is not the case. Because was chosen arbitrary, the sequence cannot have a limit and is therefore divergent.
We can extend this argument to any sequence that is unbounded, since we only used the property that becomes arbitrary large. Remember the definition of an unbounded sequence:
We can use this property to prove the following theorem:
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Convergent sequences are bounded
Proof by contraposition
The above theorem tells us that unbounded sequences are divergent. With the aid of logical contraposition, we can follow that convergent sequences must be bounded. The principle of contraposition is:
The theorem is the following implication
Using contraposition we obtain the equivalent statement:
But this means that
If you are not sure that contraposition works just make the truth table of and compare it to that of . As an example: "If it rains (), the ground is wet ()." The contraposition is: "If the gound is not wet (), it doesn't rain ()." This two statements are logically equivalent.
So by contraposition the following theorem is true, which we will need to prove further results later on:
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Alternative direct proof
We also want to show an alternative, direct way of proving that a convergent sequences is bounded. This proof is often given in other textbooks. It shows how one can use the -definition of the limit in a proof.
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