Topology/Manifolds

Template:Navigation The surface of a sphere and a 2-dimensional plane, both existing in some 3-dimensional space, are examples of what one would call surfaces. A topological manifold is the generalisation of this concept of a surface. If every point in a topological space has a neighbourhood which is homeomorphic to an open subset of ${ℝ}^n$, for some non-negative integer $n$, then the space is locally Euclidean. This formalises the idea that, while a surface might be unusually connected, patches of the surface can still resemble a euclidean space. For instance, the surface of a Klein bottle cannot be immersed in three dimensions without intersecting itself, and there is no distinction between the inside and the outside of a Klein bottle, but small patches of it still look like a euclidean space. A small creature living on the surface of a Klein bottle may not be aware of how it is connected overall or how it curves, but it could still make a rectangular or square map of its immediate area and use the map to measure lengths and directions and so forth.

A topological manifold is a locally-Euclidean Hausdorff space. Other properties are usually included in the definition of a topological space, such as being second-countable (having a countable base), which is included in the definition below. A topological manifold being Hausdorff excludes some pathological examples, such as the line with two origins, which is created by replacing the origin of the real line with two points. Any neighbourhood of either of the two origin points will contain all points in some open interval around zero, and thus will contain the other origin point, so their neighbourhoods will always intersect, so the space is not Hausdorff. See Non-Hausdorff manifold for other examples.

Note: As a convention, the ball $B^0$ is a single point. Any space with the discrete topology is a 0-dimensional manifold.

Note also that all topological manifolds are clearly locally connected.

To emphasize that a given manifold $M$ is $n$-dimensional, we will use the shorthand $M^n$. This is not to be confused with an $n$-ary cartesian product $M\times ...\times M$. However, we will prove later that such a construction does exist as well.

The alert reader may wonder why we require the manifold to be Hausdorff and second-countable. The reason for this is to exclude some pathological examples. Two such examples are the long line, which is not second-countable, and the line with two origins, which is not Hausdorff.

Proof: Since all topological manifolds are clearly locally connected, the theorem immediately follows. Template:Unicode

Given a pair $(M,A)$, where $M$ is an $n$-manifold and $A$ is an atlas on $M$, properties that $M$ may satisfy are often expressed as properties of the transition functions between charts in $A$. This is how we will define our notion of a differentiable manifold.

Note that in a smooth atlas, all transition functions are diffeomorphisms.

A chart $(V,\psi )$ with the property described above is said to be compatible with $A$.

Proof: We have to show that the transition functions between any pair of charts in $A_{\mathrm{m}\mathrm{a}\mathrm{x}}$ are smooth. This is obvious if one of then is in$A$, so let $(V_1,{\psi }_1)$ and $(V_2,{\psi }_2)$ be charts in $A_{\mathrm{m}\mathrm{a}\mathrm{x}}$ that are not in $A$, such that $V_1\cap V_2\ne \mathrm{\varnothing }$. Let $(U,\varphi )\in A$ be a chart such that $U\cap V_1\cap V_2=W\ne \mathrm{\varnothing }$. Then $\varphi \circ {\psi }_1^{-1}{|}_W$ and ${\psi }_2\circ {\varphi }^{-1}{|}_W$ are both smooth, since, both $(V_1,{\psi }_1)$ and $(V_2,{\psi }_2)$ are compatible with $A$. Then, ${\psi }_2\circ {\psi }_1^{-1}{|}_W={\psi }_2\circ ({\varphi }^{-1}\circ \varphi )\circ {\psi }_1^{-1}{|}_W=({\psi }_2\circ {\varphi }^{-1}{|}_W)\circ (\varphi \circ {\psi }_1^{-1}{|}_W)$ is smooth since it is a composition of smooth maps. An identical argument for ${\psi }_1\circ {\psi }_2^{-1}$ completes the proof. Template:Unicode

It should be obvious that if $A^{\prime }$ is a smooth atlas containing a smooth atlas $A$, then $A_{\mathrm{m}\mathrm{a}\mathrm{x}}^{\prime }=A_{\mathrm{m}\mathrm{a}\mathrm{x}}$.

Smooth maps

Proof: $f$ is continuous since $\psi \circ f\circ {\varphi }^{-1}$ is smooth and thus continuous and $\varphi$ and $\psi$ are homeomorphisms. Let $(U^{\prime },{\varphi }^{\prime })$ and $(V^{\prime },{\psi }^{\prime })$ be two other charts at $p$ and $f(p)$. Then $({\psi }^{\prime }\circ f\circ {{\varphi }^{\prime }}^{-1})=({\psi }^{\prime }\circ {\psi }^{-1})\circ (\psi \circ f\circ {\varphi }^{-1})\circ (\varphi \circ {{\varphi }^{\prime }}^{-1})$ which is a composition of smooth functions since the atlases on $M$ and $N$ are smooth, and is therefore smooth. Template:Unicode

Proof: Let $(U,\varphi )$, $(V,\psi )$ and $(W,\xi )$ be charts on $M,N,P$ at $p,f(p),g\circ f(p)$ respectively. Then $\xi \circ g\circ f\circ {\varphi }^{-1}(\varphi (p))=(\xi \circ g\circ {\psi }^{-1})\circ (\psi \circ f\circ {\varphi }^{-1})(\varphi (p))$ which is a composition of smooth maps of euclidean space and is hence smooth. Template:Unicode

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